(r^2+2r-5)(3r-2)=

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Solution for (r^2+2r-5)(3r-2)= equation:


Simplifying
(r2 + 2r + -5)(3r + -2) = 0

Reorder the terms:
(-5 + 2r + r2)(3r + -2) = 0

Reorder the terms:
(-5 + 2r + r2)(-2 + 3r) = 0

Multiply (-5 + 2r + r2) * (-2 + 3r)
(-5(-2 + 3r) + 2r * (-2 + 3r) + r2(-2 + 3r)) = 0
((-2 * -5 + 3r * -5) + 2r * (-2 + 3r) + r2(-2 + 3r)) = 0
((10 + -15r) + 2r * (-2 + 3r) + r2(-2 + 3r)) = 0
(10 + -15r + (-2 * 2r + 3r * 2r) + r2(-2 + 3r)) = 0
(10 + -15r + (-4r + 6r2) + r2(-2 + 3r)) = 0
(10 + -15r + -4r + 6r2 + (-2 * r2 + 3r * r2)) = 0
(10 + -15r + -4r + 6r2 + (-2r2 + 3r3)) = 0

Combine like terms: -15r + -4r = -19r
(10 + -19r + 6r2 + -2r2 + 3r3) = 0

Combine like terms: 6r2 + -2r2 = 4r2
(10 + -19r + 4r2 + 3r3) = 0

Solving
10 + -19r + 4r2 + 3r3 = 0

Solving for variable 'r'.

The solution to this equation could not be determined.

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